4th Class

*   Quadrilateral     The geometrical figure having four sides are called quadrilateral. Look at the following figures:           * Properties of Quadrilaterals 
  • A quadrilateral has four sides.
  • A quadrilateral has four vertices.
  • A quadrilateral has four angles.
  • Sum of all four angles of a quadrilateral is \[\text{36}0{}^\circ \]
   
  • Sides of the quadrilateral ABCD are AB, BC, CD, and AD
  • Vertexes of the quadrilateral ABCD are point A, point B, point C and point D
  • Angles of the quadrilateral are\[\angle \text{ABC}\], \[\angle \text{BCD},\text{ }\angle \text{CDA},\]and\[\angle \text{DAB}\]
  • Sum of all the four angles of the quadrilateral ABCD , \[\angle \text{A}+\angle \text{B}+\angle \text{C}+\angle \text{D}=\]\[\text{6}0{}^\circ +\text{12}0{}^\circ +\text{8}0{}^\circ +\text{1}00{}^\circ =\text{36}0{}^\circ \]  
    * more...

*   Angle     Inclination between two rays having common end point is called angle.     In the above picture, OP and OR are two rays which have a common end point 0. The inclination between the rays OP and OR is called angle POR and it is denoted as . Point O is called vertex and rays OP and OR are called arms of the angle POR.     * Features of an Angle
  • Angles is measured in degree.
  • Symbol of the degree is "°".
  • Measure of an angle is written as  a° where a is a number. Ex: 45 degree is written as 45°.
  * Types of Angles Angles have been classified into following groups based more...

*   Triangle     The geometrical shapes having three sides are called triangles.     * Properties of a Triangle
  • A triangle has three sides.
  • A triangle has three angles.
  • A triangle has three vertexes.
  • Sum of all the three angles of a triangle is\[\text{18}0{}^\circ \].
   
  • Three sides of the triangle ABC are AB, BC, and CA
  • Three angles of the triangle are\[\angle \text{ABC}\], \[\angle \text{BCA}\], and \[\angle \text{CAB}\]
  • Three vertexes of the triangle are point A, point B, and point C
  • Sum of the all three angles of the triangle ABC, \[\angle \text{ABC}+\angle \text{BCA}+\angle \text{CAB}\] \[=\text{6}0{}^\circ +\text{4}0{}^\circ +\text{8}0{}^\circ =\text{18}0{}^\circ \]
    * Types of Triangle Triangles are classified:

*   Problem Based on Unitary Method         If Jack types 75 words in 1 minute. How much time will he take to type 33750 words?   Solution:                                                                                                \[\because\] Jack types 75 words in 1 minute.                                                                                               \[\therefore\] He will type 33750 words in \[\frac{33750}{75}\] minutes. Thus, Jack will take 450 minutes to type 33750 words.         If 15 computers costs Rs. 29250, find the cost of 12 computers.   Solution: Cost of 15computers = Rs. 29250 Cost of 1 computer = Rs. \[\frac{29250}{15}\] = Rs. 1950 Therefore, cost of 12 computers = Rs. \[\text{195}0\times \text{12}\] = Rs. 23400         A train is running at a uniform speed. It covers 324567 km more...

*     Introduction     Unitary method is a method under which a Arithmetic operations are carried out to find the value of number of items by first finding the value of one item. Through daily life experience we know that when we increase the quantity of articles, their value increases and when we decrease the quantity of articles, their value decreases in other word more articles have more values and less articles have less values. Let cost of 5 pencil is Rs. 10, if we increase the number of pencils their cost is increase and if we decrease the number of pencils, their cost is decrease. Like if we buy 6 pencils we have to pay Rs. 12 and if we buy 4 pencils we have to pay Rs. 8.     In unitary method: To get more value we multiply. To get less value more...

*    Addition of Rupees to Paise and vice versa     In addition of rupees to paise or paise to rupees/ either paise is converted into rupees or rupees is converted to paise then addition is performed.       Add Rs. 525 and 45 paise Solution: Rs. \[\text{525}=\text{525}\times \text{1}00\text{ p}=\text{525}00\text{ p}\] Now add 52500 p to 45 p \[=\text{ 525}00\text{ }+\text{ 45}\] = 52545 paise = Rs. 525.45 Or 45 paise = Rs. \[\frac{45}{100}\] = Rs. 0.45 Now add Rs 525 to Rs. 0.45 = Rs. 525+ Rs. 0.45 = Rs. 525.45       * Money Based Problems       Add  Rs. 123.25, Rs. 85.60, and Rs. 48.75. Solution: \[\begin{align}   & \,\text{123}.\text{25} \\  & \,\,\,\text{85}.\text{6}0 \\  & \,\,\,\text{48}.\text{75} \\  & more...

*   Conversion of Paise into Rupees     To convert the paise into rupees we divide the given paise by 100.     Convert 435 paise into rupees.   Solution: Divide 435 by 100 Thus 435 paise =Rs. \[\frac{435}{100}=\] Rs. 4.35       Convert 23 paise into rupees.   Solution: Paise= Rs. \[\frac{23}{10}=\] Rs. 0.23

*   Conversion of Rupees into Paise     To convert rupees into paise, we multiply Rs. by 100.       Convert Rs. 5 into paise.   Solution: Multiply 5 by 100 Thus Rs. \[\text{5}=\text{5}\times \text{1}00\text{ p}\] \[=\text{ 5}00\text{p}\]       Convert Rs. 434.80 into paise.   Solution:  Rs. 434.80\[~=\text{434}.\text{8}0\times \text{1}00\text{ p}\] \[=\text{43},\text{48}0\text{ p}\]  
Rs. \[1=1\times 100p=100p\] Rs. \[3.50=3\times 100p+50p=350p\]
Rs. \[2=2\times 100p=200p\] more...
*     Introduction     We require a number of things in our day to day life. We buy these things from the market and in return we pay money as per the rate of the article. So understanding on money is of great important for us. Let us study about the money. Different countries uses different currencies. Indian currency is known as rupees. Short form of the rupees is Rs. we write 78 rupees as Rs. 78. One rupees is equal to hundred paise. Symbol of rupees is "Rs." and Symbol of the paise is "p". We write 65 paise as 65p. Rs. 1 = 100 paise. Or 1 p = Rs. 0.01 When we write rupees and paise together, for example 60 rupees and 70 paise, we write Rs. 60 and 70 P or Rs. 60.70. Rupees and paise are separated by a dot (.). Paise is more...

*     Division of a Decimal by the Power of 10       Case 1: When a decimal is divided by 10. Like \[\text{5456}.\text{32}\div \text{1}0\] The decimal is shifted one digit left. Thus \[\text{5456}.\text{32}\div \text{1}0=\text{545}.\text{632}\]     Case 2: When a decimal is divided by 100. Like \[\text{5456}.\text{32}\div \text{1}00\] The decimal is shifted two digit left. Thus\[\text{5456}.\text{32}\div \text{1}00=\text{54}.\text{5632}\]     Case 3:  When a decimal is divided by 1000. Like\[~\text{5456}.\text{32}\div \text{1}000\] The decimal is shifted three digit left. Thus \[\text{5456}.\text{32}\div \text{1}000=\text{5}.\text{45632}\]   Note: As you increase the power of 10 by one, the decimal point shift one digit left. For example: \[5463.23\div {{10}^{1}}=546.323\] \[5463.23\div {{10}^{2}}=54.6323\] \[5463.23\div {{10}^{3}}=5.46323\]       Divide 786.45 by 100 Solution: 100 contains two zeroes, therefore, shift the point two digit left in the decimal. Thus\[\text{786}.\text{45}\div \text{1}00=\text{7}.\text{8645}\]         more...


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