Projection of PQ is \[P'Q'=PQ\cos \,\theta \]
\[=({{x}_{2}}-{{x}_{1}})\cos \alpha +({{y}_{2}}-{{y}_{1}})\cos \beta +({{z}_{2}}-{{z}_{1}})\cos \gamma \]
\[=({{x}_{2}}-{{x}_{1}})l+({{y}_{2}}-{{y}_{1}})m+({{z}_{2}}-{{z}_{1}})n\].
For x-axis,\[l=1,\,\,m=0,\,\,n=0\].
Hence, projection of PQ on x-axis \[={{x}_{2}}-{{x}_{1}}\].
Similarly, projection of PQ on y-axis \[={{y}_{2}}-{{y}_{1}}\] and projection of PQ on z-axis \[={{z}_{2}}{{z}_{1}}\].
(1) Internal division : If \[P(x,y)\] divides the segment AB internally in the ratio of \[{{m}_{1}}:{{m}_{2}}\]\[\Rightarrow \]\[\frac{PA}{PB}=\frac{{{m}_{1}}}{{{m}_{2}}}\]
The co-ordinates of \[P(x,y)\] are
\[x=\frac{{{m}_{1}}{{x}_{2}}+{{m}_{2}}{{x}_{1}}}{{{m}_{1}}+{{m}_{2}}}\] and \[y=\frac{{{m}_{1}}{{y}_{2}}+{{m}_{2}}{{y}_{1}}}{{{m}_{1}}+{{m}_{2}}}\]
(2) External division : If \[P(x,y)\]divides the segment AB externally in the ratio of \[{{m}_{1}}:{{m}_{2}}\]\[\Rightarrow \]\[\frac{PA}{PB}=\frac{{{m}_{1}}}{{{m}_{2}}}\]\[\]
The co-ordinates of \[P(x,y)\] are
\[x=\frac{{{m}_{1}}{{x}_{2}}-{{m}_{2}}{{x}_{1}}}{{{m}_{1}}-{{m}_{2}}}\] and \[y=\frac{{{m}_{1}}{{y}_{2}}-{{m}_{2}}{{y}_{1}}}{{{m}_{1}}-{{m}_{2}}}\]
Then, \[PA=\sqrt{({{y}^{2}}+{{z}^{2}})}\]
\[PB=\sqrt{({{z}^{2}}+{{x}^{2}})}\]
\[PC=\sqrt{({{x}^{2}}+{{y}^{2}})}\]
The planes \[XOY,YOZ\] and \[ZOX\]are known as xy-plane, yz-plane and zx-plane respectively.
Also,\[OA=x,\,\,OB=y,\,\,OC=z\].
The three co-ordinate planes (\[XOY,YOZ\] and\[ZOX\]) divide space into eight parts and these parts are called octants.
Sign of co-ordinates of a point : The signs of the co-ordinates of a point in three dimension follow the convention that all distances measured along or parallel to \[OX,\,\,OY,\,\,OZ\] will be positive and distances moved along or parallel to \[OX',\,\,OY',\,\,OZ'\] will be negative.
(2) Cylindrical co-ordinates : If the rectangular cartesian co-ordinates of \[P\] are \[(x,y,z),\] then more...
Then, \[{{(PQ)}^{2}}=r_{1}^{2}+r_{2}^{2}-2{{r}_{1}}{{r}_{2}}\cos ({{\theta }_{1}}-{{\theta }_{2}})\]
\[\therefore \] \[PQ=\sqrt{r_{1}^{2}+r_{2}^{2}-2{{r}_{1}}{{r}_{2}}\cos ({{\theta }_{1}}-{{\theta }_{2}})}\],
where \[{{\theta }_{1}}\] and \[{{\theta }_{2}}\] in radians.
If \[(x,\,\,y)\] are the cartesian co-ordinates of a point P, then
\[x=r\,\cos \theta ;\,\,y=r\sin \theta \]
and \[r=\sqrt{{{x}^{2}}+{{y}^{2}}};\,\,\,\theta ={{\tan }^{-1}}\left( \frac{y}{x} \right)\].
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