Clearly, \[f:A\to B\] is a one-one function. But \[g:X\to Y\] is not one-one function because two distinct elements \[{{x}_{1}}\] and \[{{x}_{3}}\] have the same image under function \[g\].
(i) Method to check the injectivity of a function
Step I : Take two arbitrary elements \[x,\,\,y\] (say) in the domain of \[f\].
Step II : Put \[f(x)=f(y).\] more...
Range = For all values of \[x,\] all possible values of \[f(x)\].
(1) Methods for finding domain and range of function
(i) Domain
(a) Expression under even root (i.e., square root, fourth more...
(2) Closed interval : Let a and b be two real numbers such that \[a<b,\] then the set of all real numbers lying between \[a\] and \[b\] including \[a\] and \[b\] is called a closed interval and is denoted by \[[a,\,\,b]\]. Thus, \[[a,\,\,b]=\{x\in R\,:\,a\le x\le b\}\]
(3) Open-Closed interval : It is denoted by \[[a,\,\,b]\] or \[(a,\,\,b]\] and \[[a,\,\,b]\] or \[(a,\,\,b]=\{x\in R\,:\,\,a<x\le b\}\].
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