Category : 12th Class
Mathematical Operations
Introduction: This is a new type of verbal reasoning question which is being frequently asked in the various competitive examination. Here, a mathematical symbols is damaged with another symbol to confuse and then you are asked to solve an equation using the new instructions with changed symbols.
Example:
(a) 5 (b) 22
(c) 48 (d) 52
Ans. (c)
Explanation: Using the correct symbols, we have:
Given expression = \[15\,\,\times \,\,3\,\,-\,\,10\,\,\div \,\,5\,\,+\,\,5\,\,=\,\,45-2\,\,+\,\,5\,\,=\,\,50-2=\text{ }48.\]
(a) 1 (b) \[\,7\frac{2}{5}\]
(c) \[\,8\frac{3}{5}\] (d) 44
Ans. (b)
Explanation: Using the correct symbol, we have :
Given expression = \[8\,\,+\,\,7\,\,\times \,\,8\text{ }40\,\,\,\div \,\,\,2\,\,=\,\,8\,\,+\,\,7\times \frac{1}{5}\,\,-\,\,2\,\,\,\,=\,\,\,\,6+\frac{7}{6}\,\,=\frac{37}{5}\,\,=\,\,7\frac{2}{5}.\]
(a) 18 (b) 28
(c) 31 (d) 103
Ans. (b)
Explanation: Using the correct symbols, we have:
Given expression \[=\text{ }30\,\,\div \,\,2+3\,\,\times \,\,6\,\,-\,\,5\,\,=\,\,15\,\,+\,\,18\,\,-\,\,5\,\,=\,\,28.\]
(a) - 30 (b) - 21
(c) 15 (d) 45
Ans. (b)
Explanation: Using the correct symbols, we have:
Given expression \[=\text{ }12\text{ }-\text{ }12\text{ }\times \text{ }28\text{ }\div \text{ }7\text{ }+\text{ }15\text{ }=\text{ }12\text{ }-\text{ }12\text{ }\times \text{ }4\text{ }+\text{ }15\]
\[=12\,\,-\,\,48\,\,+\,\,15\,\,=\,\,27\,\,-\,\,48\,\,=-21.\]
(a) 25 (b) 27
(c) 29 (d) 36
Ans. (b)
Explanation: Using the correct symbols, we have:
Given expression = \[16\text{ }+\text{ }4\text{ }\times \text{ }5\text{ }-\text{ }72\text{ }\div \text{ }8\text{ }=\text{ }16\text{ }+\text{ }20\text{ }-\text{ }9\text{ }=\text{ }36\text{ }-\text{ }9\text{ }=\text{ }27.\]
Snap Test
(a) \[3\,\,\times \,\,4\,\,>\,\,2\,\,-\,\,9\,\,+\,\,3\,\,<\,\,3\]
(b) \[5\,\,\times \,\,3\,\,<\,\,7\,\,\div \,\,8+4\,\,\times \,\,1\]
(c) \[5\,\,>\,\,2+2=10<4\,\,\times \,\,8\]
(d) \[3\,\,\times \,\,2\,\,<\,\,4\,\,\div \,\,16\,\,>\,\,2+4\]
Ans. (c)
Explanation: We get the statement as:
\[5\,\,\times \,\,2\,\,\div \,\,2\,\,<\,\,10\,\,-\,\,4+8\,\,or\,\,5\,\,\times \,\,1\,\,<\,\,18\,\,-\,\,4\,\,or\,\,5<14\], which is true.
(a) \[4\,\,\times \,\,5\,\,+\,\,9\,\,-\,\,3\,\,\div \,\,4\,\,=\,\,15\]
(b) \[4\,\,\times \,\,5\,\,\times \,\,9\,\,+\,\,3\,\,\div \,\,4\,\,=\,\,11\]
(c) \[4-5\,\,\div \,\,9\,\,\times \,\,3\,\,-\,\,4=17\]
(d) \[4\,\,\div \,\,5\,\,+\,\,9\,\,-\,\,3\,\,+\,\,4\,\,=\,\,18\]
Ans. (a)
Explanation: We get the statement as:
\[4\,\,+\,\,5\,\,\times \,\,9\,\,\div \,\,3-4=4\,\,+\,\,5\,\,\times \,\,3-4\,\,=\,\,4+15\,\,-\,\,4\text{ }=15.\]
(a) 30 (b) 20
(c) 10 (d) 5
Ans. (b)
Explanation: Using the correct symbols we have given expression \[=\text{ }\left( 7\text{ }\times \text{ }3 \right)\,\,-\,\,6\,\,+\,\,5\,\,=\,\,21\,\,-\,\,6\,\,+\,\,5\,\,\,=\,\,20\]
(a) \[36-12\,\,\times \,\,6\,\,\div \,\,3+4=60\]
(b) \[36\,\,\times \,\,4\,\,-\,\,12\,\,+\,\,5\,\,\div \,\,3\,\,=\,\,420\]
(c) \[43\,\,\times \,\,7\,\,\div \,\,5\,\,+\,\,4\,\,-\,\,9\,\,=\,\,25\]
(d) \[52\,\,\div \,\,4\,\,+\,\,5\,\,\times \,\,8\,\,-\,\,2\,\,=\,\,36\]
Ans. (d)
Explanation: We get the statement.
\[=52-4\,\,\times \,\,5+8\,\,\div \,\,2\]
\[=52-4\,\,\times \,\,5\,\,+\,\,4\]
\[=52-20+4=36\]
(a) \[16-5\,\,\times \,\,10\,\,\div \,\,4\,\,\div \,\,4\,\,=\,\,12\] (b) \[16+5-10\,\,\times \,\,4\,\,\div \,\,3=9\]
(c) \[16\,\,+\,\,5\,\,\div \,\,10\,\,\times \,\,4\,\,-\,\,3\,\,=\,\,9\] (d) \[16\,\,\times \,\,5\,\,\div \,\,10\,\,+\,\,4\,\,-\,\,3\,\,=\,\,19\]
Ans. (b)
Explanation: We get the statement as
\[=\,\,\,16\,\,\times \,\,5\div 10+4-3\]
\[=16\,\,\times \,\,\frac{1}{2}\,\,+\,\,4\,\,-\,\,3\]
\[=8+4-3=9.\]
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