10th Class

Quadratic Equations

Category : 10th Class

Quadratic Equations

 

 

 

  • Quadratic equation: An equation of the form \[a{{x}^{2}}+bx+c=0\] where a, b and\[c\in R\]and \[a\ne 0\]is called a quadratic equation.

If p(x) is a quadratic polynomial, then p(x) = 0 is called a quadratic equation.

Note: (i) An equation of degree 2 is called a quadratic equation.

(ii) The quadratic equation of the form \[a{{x}^{2}}+bx+c=0\].

Solution or roots of a quadratic equation: If p(x) = 0 is a quadratic equation, then the zeros of the polynomial p(x) are called the solutions or roots of the quadratic equation p(x)=0.

 

Note: (i) Since the degree of a quadratic equation is 2, it has 2 roots or solutions.

(ii) x = a is the root of p(x) = 0, if p(a) = 0.

(iii) Finding the roots of a quadratic equation is called solving the quadratic equation.

 

  • Methods of solving a quadratic equation: There are different methods of solving a quadratic equation.

(a) Factorization method

(i) Splitting the middle term        

(ii) Completing the square

(b) Formula method

(a) (i) Splitting the middle term: Consider the quadratic equation\[a{{x}^{2}}+bx+c=0\].

Step 1: Find the product of the coefficient of\[{{x}^{2}}\]and the constant term i.e., ac.

Step 2: (a) If ac is positive, then choose two factors of ac, whose sum is equal to b (the coefficient of the middle term).

(b)  If ac is negative, then choose two factors of ac, whose difference is equal to b (the coefficient of the middle term).

Step 3: Express the middle terms as the sum (or difference) of the two factors obtained in step 2. [Now the quadratic equation has 4 terms]

  • Step 4: Separate the term common to the first two terms and then write the first two terms as a product. Take the common term (binomial) out of the last two terms and get another factor so that the last two terms are written as a product.

Step 5: Express the given quadratic equation as a product of two binomials, and solve them.

Step 6: The two values obtained in step 5 are the roots of the given quadratic equation.

Note: An important property used in solving a quadratic equation by splitting the middle term.

"If ab = 0, then either a = 0, or b = 0 or both a and b are 0, where 'a' and 'b' are real numbers"

(ii) Completing the square: In some cases where the given quadratic equation can be solved by factorization, a suitable term is added and subtracted. Then terms are regrouped in such a manner that a square is completed by three of the terms. The equation is then solved using factorization method.

 

Note: Usually, the term added and subtracted is the square of half the coefficient of x.

 

  1. Formula method: The roots of a quadratic equation\[a{{x}^{2}}+bx+c=0\]are given by \[\frac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\]provided\[{{b}^{2}}-4ac\ge 0\]. This formula for finding the roots of a quadratic equation is called the quadratic formula.

Note: The roots of the quadratic equation using the quadratic formula are

\[x=\frac{-b\sqrt{{{b}^{2}}-4ac}}{2a}\]and\[x=\frac{-b-\sqrt{{{b}^{2}}-4ac}}{2a}\]

Nature of roots: For a quadratic equation \[a{{x}^{2}}+bx+c=0,\]\[{{b}^{2}}-4ac\](denoted by D) is called the discriminate.

Value of Discriminate

Roots

Nature of roots

No. of Roost

Greater than (positive)

\[\frac{-b+\sqrt{{{b}^{2}}-4ac}}{2a}\]and \[\frac{-b-\sqrt{{{b}^{2}}-4ac}}{2a}\]

Real and distinct

2

Lesser than 0 (Negative)

\[\frac{-b+i\sqrt{|D|}}{2a}\]and \[\frac{-b-i\sqrt{|D|}}{2a}\]

Complex or imaginary

0

Equal to 0

\[\frac{-b}{2a},\frac{-b}{2a}\]

Real and

2 coincident roots or repeated roots

 

If \[{{\text{b}}^{\text{2}}}-\text{4ac}>0\], then \[\sqrt{{{b}^{2}}-4ac}\]is a real number and the quadratic equation \[a{{x}^{2}}+bx+c=0\]has two real roots a and p.

If \[{{\text{b}}^{\text{2}}}-\text{4ac}<0\], then \[\sqrt{{{\text{b}}^{\text{2}}}-\text{4ac}}\] is not a real number and the quadratic equation \[a{{x}^{2}}+bx+c=0\] has no real root.

  • Quadratic equations can be applied to solve word problems.

 

Note: Any root of the quadratic equation that does not satisfy the condition of the problem is discarded.

 


Archive



You need to login to perform this action.
You will be redirected in 3 sec spinner