Equations of Motion
The motion of the body moving along a straight line with uniform acceleration can be described by three equations of motion. These equations can be derived as follows.
First Equation of Motion
Let us consider an object moving with a initial velocity 'u'. If it is subjected to a uniform accleration 'a' such that it attains a velocity of V after time 't', then
Acceleration \[=\frac{Final\,velocity\,-\,initial\,ve\operatorname{lo}city}{Time\,taken}\]
So, \[a=\frac{v-u}{t}\]
\[\Rightarrow \,\,at=v-u,\] or \[v=u+at\]
where, v = final velocity of the body
u = Initial velocity of the body
a = acceleration
and, t= time taken
Second Equation of Motion
The second equation of motion is: \[s=ut+\frac{1}{2}\,a{{t}^{2}}\]. It gives the distance traveled by a body in time t.
Let us derive this second equation of motion:
Let us consider an object moving with a initial velocity 'u' and a uniform acceleration "a". Let it attains a velocity V after some time 't'. Let the distance traveled by the object in this time be 's'. The distance traveled by a moving body in time 't' can be found out by considering its average velocity. Since the initial velocity of the body is 'u' and its final velocity is V, the average velocity is given by:
Average velocity \[=\frac{\text{Initial velocity }+\text{ final velocity}}{2}\]
i.e., Average velocity \[=\frac{u+v}{2}\]
Also, Distance traveled = Average velocity \[\times \] Time
so, \[S=\,\left( \frac{u+v}{2} \right)\times t\] …(1)
From the first equation of motion we have, v = u + at. Putting this value of ‘v’ in equation (1), we get:
Or \[S=\,\left( \frac{u+v}{2} \right)\times t\]
Or \[S=\,\left( \frac{2u+at}{2} \right)\times t\]
Or \[S=\frac{2ut+a{{t}^{2}}}{2}\]
Where s = distance traveled by the body in time t
u = Initial velocity of the body and, a = Acceleration
Third Equation of Motion
The third equation of motion is: v- u^ 2as. It gives the velocity acquired by a body in traveling a distance 's'.
The third equation of motion can be obtained by eliminating -f from the first two equations of motion and using the second equation of motion
From the second equation of motion we have:
\[s=ut+\frac{1}{2}\,a{{t}^{2}}\] …(1)
And from the first equation of motion we have :
\[v=u+at\]
Or, \[at=v-u\]
Or, \[t=\frac{v-u}{a}\]
Putting this value of t in equation (1), we get:
\[S=u\,\left( \frac{v-u}{a} \right)+\frac{1}{2}a\,{{\left( \frac{v-u}{a} \right)}^{2}}\]
Or \[S=u\,\left( \frac{v-u}{a} \right)+\frac{1}{2}\,\frac{{{(v-u)}^{2}}}{a}\]
Or \[S=\frac{uv-{{u}^{2}}+{{v}^{2}}+{{u}^{2}}-2uv}{2a}\]
Or \[2as={{v}^{2}}-{{u}^{2}}\]
Or \[{{v}^{2}}={{u}^{2}}+\,2as\]
Where, v = final velocity,
u = initial velocity,
a = acceleration
and s = distance traveled
Graphical Method of Finding Equations of Motion
We can derive the equation of motions using the velocity time graph. Consider the motion
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