Category : JEE Main & Advanced
The sum of n terms of the series
\[a+(a+d)+(a+2d)+.......+\{a+(n-1)\,d\}\] is given by
\[{{S}_{n}}=\frac{n}{2}[2a+(n-1)\,d]\]
Also, \[{{S}_{n}}=\frac{n}{2}(a+l)\], where \[l=\] last term \[=a+(n-1)d\].
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