# Solved papers for NEET Physics Elasticity NEET PYQ-Elasticity

### done NEET PYQ-Elasticity Total Questions - 6

• question_answer1) The following four wires are made of the same material. Which of these will have the largest extension when the same tension is applied? [NEET 2013]

A)
Length = 50 cm, diameter = 0.5 mm

B)
Length = 100 cm, diameter = 1 mm

C)
Length = 200 cm, diameter = 2 mm

D)
Length = 300 cm, diameter = 3 mm

• question_answer2) Copper of fixed volume V is drawn into wire of length $l$. When this wire is subjected to a constant force F, the extension produced in the wire is$\Delta l$. Which of the following graphs is a straight line? [NEET 2014]

A)
$\Delta l$ versus $\frac{1}{l}$

B)
$\Delta l$ versus ${{l}^{2}}$

C)
$\Delta l$ versus $\frac{1}{{{l}^{2}}}$

D)
$\Delta l$ versus $l$

• question_answer3) The approximate depth of an ocean is 2700 m. The compressibility of water is $45.4\times {{10}^{-11}}P{{a}^{-1}}$ and density of water is ${{10}^{3}}kg/{{m}^{3}}$. What fractional compression of water will be obtained at the bottom of the ocean?[NEET 2015 (C)]

A)
$0.8\times {{10}^{-2}}$

B)
$1.0\times {{10}^{-2}}$

C)
$1.2\times {{10}^{-2}}$

D)
$1.4\times {{10}^{-2}}$

• question_answer4) Two wires are made of the same material and have the same volume. The first wire has cross-sectional area A and the second wire has cross-sectional area 3A. If the length of the first wire is increased by $\Delta /$on applying a force F, how much force is needed to stretch the second wire by the same amount?                 [NEET - 2018]

A)
4 F

B)
6 F

C)
9 F

D)
F

• question_answer5) When a block of mass M is suspended by a long wire of length L, the length of the wire becomes$(L+l)$. The elastic potential energy stored in the extended wire is-                      [NEET 2019]

A)
$\frac{1}{2}Mgl$

B)
$\frac{1}{2}MgL$

C)
$Mgl$

D)
$MgL$

• question_answer6) A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to ${{L}_{1}}$when mass M is suspended from its free end. The expression for Youngs modulus is :          [NEET 2020]

A)
$\frac{Mg\left( {{L}_{1}}-L \right)}{AL}$

B)
$\frac{MgL}{A{{L}_{1}}}$

C)
$\frac{MgL}{A\left( {{L}_{1}}-L \right)}$

D)
$\frac{Mg{{L}_{1}}}{AL}$