A) \[0.8\times {{10}^{-2}}\]
B) \[1.0\times {{10}^{-2}}\]
C) \[1.2\times {{10}^{-2}}\]
D) \[1.4\times {{10}^{-2}}\]
Correct Answer: C
Solution :
| Given \[d=2700\,m\] |
| \[\rho ={{10}^{3}}kg/{{m}^{3}}\] |
| Compressibility \[=45.4\times {{10}^{-11}}\] per pascal |
| The pressure at the bottom of ocean is given by |
| \[p=\rho gd\] |
| \[={{10}^{3}}\times 10\times 2700=27\times {{10}^{6}}\,\text{Pa}\] |
| So, fractional compression = compressibility |
| \[\times \] pressure |
| \[=45.4\times {{10}^{-11}}\times 27\times {{10}^{6}}=1.2\times {{10}^{-2}}\] |
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