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  • question_answer
    A wire of length L, area of cross section A is hanging from a fixed support. The length of the wire changes to \[{{L}_{1}}\]when mass M is suspended from its free end. The expression for Young’s modulus is :          [NEET 2020]

    A)       \[\frac{Mg\left( {{L}_{1}}-L \right)}{AL}\]

    B) \[\frac{MgL}{A{{L}_{1}}}\]

    C) \[\frac{MgL}{A\left( {{L}_{1}}-L \right)}\]

    D) \[\frac{Mg{{L}_{1}}}{AL}\]

    Correct Answer: C

    Solution :

    [c] \[Stress=\frac{Mg}{A}\]
                \[Strain=\frac{\Delta L}{L}=\frac{{{L}_{1}}-L}{L}\]
    Young's modulus \[Strain=\frac{\Delta L}{L}=\frac{{{L}_{1}}-L}{L}\]


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