Question Bank for 12th Class Chemistry The p-Block Elements-I / p-ब्लॉक के कुछ तत्व-I MCQs - The p-Block Elements

1)

The decreasing order of boiling points of the following hydrides is

A)

\[{{H}_{2}}O>Sb{{H}_{3}}>As{{H}_{3}}>P{{H}_{3}}>N{{H}_{3}}\]

B)

\[{{H}_{2}}O>N{{H}_{3}}>Sb{{H}_{3}}>As{{H}_{3}}>P{{H}_{3}}\]

C)

\[{{H}_{2}}O>Sb{{H}_{3}}>N{{H}_{3}}>As{{H}_{3}}>P{{H}_{3}}\]

D)

\[{{H}_{2}}O>P{{H}_{3}}>As{{H}_{3}}>Sb{{H}_{3}}>N{{H}_{3}}\]

View Solution

2)

Fluorine is the best oxidising agent because it has

A)

highest electron affinity

B)

highest reduction potential

C)

highest oxidation potential

D)

lowest electron affinity.

View Solution

3)

A gas (X) is obtained when copper reacts with dilute \[HN{{O}_{3}}\]. The gas thus formed reacts with oxygen to give brown fumes of (Y). (Y) when dissolved in water gives an important acid (Z) and the gas (X). X, Y and Z respectively are

A)

\[NO\,\,;\,\,N{{O}_{2}}\,\,\,;\,\,HN{{O}_{3}}\]

B)

\[N{{O}_{2}}\,\,;\,\,NO\,\,;\,\,HN{{O}_{3}}\]

C)

\[{{N}_{2}}O\,\,;\,\,NO\,\,;\,\,HN{{O}_{2}}\]

D)

\[NO\,\,\,;\,\,{{N}_{2}}O\,\,;\,\,HN{{O}_{3}}\]

View Solution

4)

Nitrogen forms stable \[{{N}_{2}}\] molecule but phosphorus is converted to \[{{P}_{4}}\] from \[{{P}_{2}}\] because

A)

\[p\pi -p\pi \] bonding is strong in phosphorus

B)

\[p\pi -p\pi \]bonding is weak in phosphorus

C)

triple bond is present in phosphorus

D)

single P - P bond is weaker than N - N bond.

View Solution

5)

Match the interhalogen compounds of column I with the geometry in column II and assign the correct code.

	Column I		Column II
[A]	XX'	(i)	T-shape
[B]	\[XX{{'}_{3}}\]	(ii)	Pentagonal bipyramidal
[C]	\[XX{{'}_{5}}\]	(iii)	Linear
[D]	\[XX'{{\,}_{7}}\]	(iv)	Square pyramidal
		(v)	Tetrahedral

A)

[A]	[B]	[C]	[D]
(iii)	(i)	(iv)	(ii)

B)

[A]	[B]	[C]	[D]
(v)	(iv)	(iii)	(ii)

C)

[A]	[B]	[C]	[D]
(iv)	(iii)	(ii)	(i)

D)

[A]	[B]	[C]	[D]
(iii)	(iv)	(i)	(ii)

View Solution

6)

\[XeO{{F}_{2}}\] has the following structure

A)

B)

C)

D)

View Solution

7)

Which is the correct thermal stability order for \[{{H}_{2}}E\](E = O, S, Se, Te and Po)?

A)

\[{{H}_{2}}Se<{{H}_{2}}Te<{{H}_{2}}Po<{{H}_{2}}O<{{H}_{2}}S\]

B)

\[{{H}_{2}}S<{{H}_{2}}O<{{H}_{2}}Se<{{H}_{2}}Te<{{H}_{2}}Po\]

C)

\[{{H}_{2}}O<{{H}_{2}}S<{{H}_{2}}Se<{{H}_{2}}Te<{{H}_{2}}Po\]

D)

\[{{H}_{2}}Po<{{H}_{2}}Te<{{H}_{2}}Se<{{H}_{2}}S<{{H}_{2}}O\]

View Solution

8)

Group 16 elements have lower value of first ionisation enthalpy as compared to group 15 elements because

A)

half-filled p-orbitals in group 15 elements are more stable

B)

group 16 elements have smaller size than group 15 elements

C)

group 16 elements contain double bond while group 15 elements have triple bond

D)

group 16 elements have more number of electrons in p-orbitals.

View Solution

9)

Which of the following is not a use of noble gases?

A)

Argon is widely used for filling incandescent electric bulbs.

B)

Neon is used in safety devices for protecting electrical instruments.

C)

Radon is used in radiotherapy of cancer.

D)

Helium is filled in tubes of cycles and scooters tyres.

View Solution

10)

Which of the following is the wrong statement?

A)

Ozone is a paramagnetic gas.

B)

The two oxygen-oxygen bond length in ozone are identical.

C)

\[{{O}_{3}}\]molecule is bent shape.

D)

Ozone is violet-black in solid state.

View Solution

11)

Oganesson has been synthetically produced by collision of

A)

Ra and Ca

B)

Cf and Ca

C)

Cf and Cu

D)

Ra and He

View Solution

12)

Which of the following shows nitrogen with its increasing order of oxidation number?

A)

\[{{N}_{2}}O<NO<N{{O}_{2}}<NO_{3}^{-}<NH_{4}^{+}\]

B)

\[NH_{4}^{+}<{{N}_{2}}O<NO<N{{O}_{2}}<NO_{3}^{-}\]

C)

\[NH_{4}^{+}<{{N}_{2}}O<N{{O}_{2}}<NO_{3}^{-}<NO\]

D)

\[NH_{4}^{+}<NO<{{N}_{2}}O<N{{O}_{2}}<NO_{3}^{-}\]

View Solution

13)

Consider the following reaction taking place on heating with cone. \[{{H}_{2}}S{{O}_{4}}\].

\[{{C}_{12}}{{H}_{22}}{{O}_{11}}\xrightarrow{conc\,\,.\,\,{{H}_{2}}S{{O}_{4}}}12C+11{{H}_{2}}O\]

The above reaction shows that sulphuric acid is

A)

an oxidising agent

B)

a reducing agent

C)

a dehydrating agent

D)

a sulphonating agent.

View Solution

14)

The correct order of increasing electron affinity of halogens is

A)

\[I<Br<Cl\]

B)

\[Br<I<Cl\]

C)

\[~Cl<Br<I\]

D)

\[I<Cl<Br\]

View Solution

15)

Fill in the blanks. The noble gases can form compounds with (i) and (ii). The mixture of (iii) and (iv) is used for respiration by divers.

A)

(i)	(ii)	(iii)	(iv)
iodine	oxygen	oxygen	argon

B)

(i)	(ii)	(iii)	(iv)
fluorine	oxygen	helium	oxygen

C)

(i)	(ii)	(iii)	(iv)
xenon	platinum	Argon	krypton

D)

(i)	(ii)	(iii)	(iv)
helium	oxygen	Xenon	argon

View Solution

16)

Which of the following is not correct about xenon hexafluoride?

A)

It has oxidation state of +6.

B)

The hybridisation involved in \[Xe{{F}_{6}}\]is \[s{{p}^{3}}{{d}^{3}}\]

C)

The shape of \[Xe{{F}_{6}}\]is distorted octahedral and can be represented as

D)

On hydrolysis it gives Xe, HF and\[{{O}_{2}}\].

View Solution

17)

Which of the following is correct representation of reaction of acidified permanganate solution with sulphur dioxide?

A)

\[2MnO_{4}^{-}+5S{{O}_{2}}+2{{H}_{2}}O\to 5SO_{4}^{2-}+2M{{n}^{2+}}+4{{H}^{+}}\]

B)

\[MnO_{4}^{-}+S{{O}_{2}}+2{{H}_{2}}O\to S+M{{n}^{2+}}+4{{H}^{+}}\]

C)

\[2MnO_{4}^{-}+5S{{O}_{2}}+2{{H}_{2}}O\to 4SO_{3}^{2-}+S+2M{{n}^{2+}}+4{{H}^{+}}\]

D)

\[3MnO_{4}^{-}+2S{{O}_{2}}+2{{H}_{2}}O\to 2S+3M{{n}^{2+}}+4{{H}^{+}}\]

View Solution

18)

Which of the following statements is not correct for \[S{{O}_{2}}\] gas?

A)

It acts as bleaching agent in moist conditions.

B)

Its dilute solution is used as disinfectant.

C)

Its molecules have linear geometry.

D)

Acidified \[KMn{{O}_{4}}\] is decolourised when \[S{{O}_{2}}\] is passed through it.

View Solution

19)

Name of the synthetic radioactive element of group 16 having atomic number 116 is

A)

Livermorium

B)

Tennessine

C)

Nihonium

D)

Moscovium

View Solution

20)

Which of the following compounds will not give ammonia on heating?

A)

\[{{\left( N{{H}_{4}} \right)}_{2}}S{{O}_{4}}\]

B)

\[{{\left( N{{H}_{4}} \right)}_{2}}C{{O}_{3}}\]

C)

\[N{{H}_{4}}N{{O}_{2}}\]

D)

\[N{{H}_{4}}Cl\]

View Solution

21)

Which of the following is used to prepare \[C{{l}_{2}}\] gas at room temperature from concentrated HCl?

A)

\[Mn{{O}_{2}}\]

B)

\[{{H}_{2}}S\]

C)

\[KMn{{O}_{4}}\]

D)

\[C{{r}_{2}}{{O}_{3}}\]

View Solution

22)

Ammonia reacts with boron trifluoride to form an adduct. The bonding between \[N{{H}_{3}}\]and \[B{{F}_{3}}\]is

A)

covalent bonding

B)

coordinate bonding

C)

hydrogen bonding

D)

ionic bonding.

View Solution

23)

A)

it has high vapour pressure

B)

it comes out with brisk effervescence

C)

it is a corrosive fluid

D)

it vaporises at room temperature.

View Solution

24)

Fill in the blanks by choosing an appropriate option. (i) is a synthetic radioactive element of group 15 having electronic configuration (ii).

A)

(i)	(ii)
\[_{115}Mc\]	\[\left[ Rn \right]5{{f}^{14}}6{{d}^{10}}7{{s}^{2}}7{{p}^{3}}\]

B)

(i)	(ii)
\[_{115}Mc\]	\[\left[ Xe \right]5{{f}^{14}}6{{d}^{10}}7{{s}^{2}}7{{p}^{3}}\]

C)

(i)	(ii)
\[_{116}Lv\]	\[\left[ Rn \right]5{{f}^{14}}6{{d}^{10}}7{{s}^{2}}7{{p}^{4}}\]

D)

(i)	(ii)
\[_{114}Fl\]	\[\left[ Rn \right]5{{f}^{14}}6{{d}^{10}}7{{s}^{2}}7{{p}^{2}}\]

View Solution

25)

Dioxygen is a gas but sulphur is a solid because

A)

oxygen atom has the tendency to form multiple \[p\pi -p\pi \] bonds

B)

S - S bond is not as stable as S = S bond

C)

O - O chains are less stable than S - S chains

D)

oxygen is paramagnetic while sulphur is diamagnetic.

View Solution

26)

Match the column I with column II and mark the appropriate choice.

	Column I		Column II
[A]	Thiosulphuric acid	(i)	\[{{H}_{2}}S{{O}_{5}}\]
[B]	Caro's acid	(ii)	\[{{H}_{2}}{{S}_{2}}{{O}_{6}}\]
[C]	Marshall's acid	(iii)	\[{{H}_{2}}{{S}_{2}}{{O}_{3}}\]
[D]	Dithionic acid	(iv)	\[{{H}_{2}}{{S}_{2}}{{O}_{8}}\]

A)

[A] \[\to \] (i); [B] \[\to \] (ii); [C] \[\to \] (iii); [D] \[\to \] (iv)

B)

[A] \[\to \] (iv); [B] \[\to \] (iii); [C]\[\to \] (ii); [D]\[\to \](i)

C)

[A]\[\to \] (iii); [B] \[\to \] (i); [C] \[\to \] (iv); [D] \[\to \] (ii)

D)

[A] \[\to \] (ii); [B] \[\to \] (iii); [C] \[\to \] (i); [D] \[\to \] (iv)

View Solution

27)

Which is the correct arrangement of the compounds based on their bond strength?

A)

\[HF\text{ }>\text{ }HCl\text{ }>\text{ }HBr\text{ }>\text{ }HI\]

B)

\[HI\text{ }>\text{ }HBr\text{ }>\text{ }HCl\text{ }>\text{ }HF\]

C)

\[HCl\text{ }>\text{ }HF\text{ }>\text{ }HBr\text{ }>\text{ }HI\]

D)

\[HF\text{ }>\text{ }HBr\text{ }>\text{ }HCl\text{ }>\text{ }HI\]

View Solution

28)

Interhalogen compounds are more reactive than the individual halogens because

A)

they are prepared by direct combination of halogens

B)

X - X' bond is weaker than X-X or X'-X' bonds

C)

they are thermally more stable than halogens

D)

there is a large difference in their electronegativity.

View Solution

29)

A black powder when heated with cone. HCl gives a greenish yellow gas. The gas acts as an oxidising and a bleaching agent. When it is passed over slaked lime, a white powder is formed which is a ready source of gas. The black powder and white powder respectively are

A)

\[KCl{{O}_{3}}\]and \[NACl{{O}_{3}}\]

B)

\[Mn{{O}_{2}}\] and \[Ca{{(OCl)}_{2}}\]

C)

\[Mn{{O}_{2}}\] and \[KCl{{O}_{3}}\]

D)

\[MnC{{l}_{4}}\]and \[COC{{l}_{2}}\]

View Solution

30)

What is the correct observation when \[B{{r}_{2}}\] is treated with NaF, NaCl and NaI taken in three test-tubes labelled as (X), (Y) and (Z)?

A)

\[{{F}_{2}}\] is liberated in (X) and \[C{{l}_{2}}\] in (Y).

B)

Only \[{{I}_{2}}\] is liberated in (Z).

C)

Only \[C{{l}_{2}}\] is liberated in (Y).

D)

Only \[{{F}_{2}}\] is liberated in (X).

View Solution

31)

Which of the following statements is not correct about \[Xe{{F}_{2}}\]?

A)

It can be obtained by direct reaction between \[{{F}_{2}}\] and Xe at high pressure.

B)

\[Xe{{F}_{2}}\] undergoes alkaline hydrolysis to give \[{{O}_{2}}\] and Xe.

C)

\[Xe{{F}_{2}}\] is a powerful reducing agent.

D)

\[Xe{{F}_{2}}\] contains two bond pairs and three lone pairs.

View Solution

32)

Fill in the blanks by choosing the appropriate option. Conc. \[{{H}_{2}}S{{O}_{4}}\] chars paper, wood and sugar by removing (i) from them. It is also known as (ii). It is manufactured by (iii) process. It is a strong (iv) and (v) acid.

A)

(i)	(ii)	(iii)	(iv)	(v)
\[{{H}_{2}}O\]	oil of vitriol	contact	oxidising	dibasic

B)

(i)	(ii)	(iii)	(iv)	(v)
\[{{O}_{2}}\]	oil of vitriol	oleum	dehydrating	monobasic

C)

(i)	(ii)	(iii)	(iv)	(v)
\[{{H}_{2}}O\]	oil of olay	Solvay	dehydrating	dibasic

D)

(i)	(ii)	(iii)	(iv)	(v)
\[S{{O}_{2}}\]	oil of winter	contact	oxidising	monobasic

View Solution

33)

The hybridisation state of the central atom and shape of the molecules is given below. Mark the incorrect combination.

A)

\[S{{O}_{3}}-s{{p}^{2}}\] hybridisation, planar triangular

B)

\[S{{O}_{2}}-s{{p}^{2}}\] hybridisation, V-shaped

C)

\[{{H}_{2}}S{{O}_{4}}-s{{p}^{2}}\]hybridisation, V-shaped

D)

\[{{O}_{3}}-\,\,s{{p}^{2}}\] hybridisation, angular

View Solution

34)

Choose the correct statements from the following.

A)

Rhombic sulphur is blue in colour.

B)

Rhombic sulphur is soluble in water but insoluble in organic solvents.

C)

Rhombic and monoclinic sulphur have \[{{S}_{6}}\] molecules.

D)

In cyclo-\[{{S}_{6}}\] molecule, the ring adopts chair form.

View Solution

35)

Which of the following statements is not correct?

A)

Oxygen molecule is paramagnetic with two unpaired electrons.

B)

Sulphur shows maximum covalency of four.

C)

Ozone can be easily detected by mercury.

D)

Both sulphurous and sulphuric acid are dibasic in nature.

View Solution

36)

Sulphur molecule is

A)

diatomic

B)

triatomic

C)

tetratomic

D)

octa-atomic.

View Solution

37)

Arrange the following hydrides of group 16 elements in order of increasing stability.

A)

\[{{H}_{2}}S<{{H}_{2}}O<{{H}_{2}}Te>{{H}_{2}}Se\]

B)

\[{{H}_{2}}O<{{H}_{2}}Te<{{H}_{2}}Se<{{H}_{2}}S\]

C)

\[{{H}_{2}}O<{{H}_{2}}S<{{H}_{2}}Se<{{H}_{2}}Te\]

D)

\[{{H}_{2}}Te<{{H}_{2}}Se<{{H}_{2}}S<{{H}_{2}}O\]

View Solution

38)

In which pair of ions both the species contain S-S bond?

A)

\[{{S}_{4}}O_{6}^{2-},\,{{S}_{2}}O_{3}^{2-}\]

B)

\[{{S}_{2}}O_{7}^{2-},\,{{S}_{2}}O_{8}^{2-}\]

C)

\[{{S}_{4}}O_{6}^{2-},\,{{S}_{2}}O_{7}^{2-}\]

D)

\[{{S}_{2}}O_{7}^{2-},\,{{S}_{2}}O_{3}^{2-}\]

View Solution

39)

Which of the following is the correct combination of oxidation states for group 17 elements?

A)

+6, +4, +2, - 2

B)

+7, +5, +3, +1, - 1

C)

+7, +6, +5, +3, +2, - 2

D)

+7, +5, +4, +3, +2, - 2

View Solution

40)

Among the following, the number of compounds having zero lone pair of electrons on central atom is \[Xe{{O}_{3}}\], \[Xe{{O}_{2}}{{F}_{2}}\], \[Xe{{O}_{4}}\], \[Xe{{O}_{3}}{{F}_{2}}\], \[Xe{{F}_{4}}\]

A)

2

B)

3

C)

4

D)

zero.

View Solution

41)

The oxidation state of nitrogen is - 1/3 in

A)

\[{{N}_{3}}H\]

B)

\[N{{H}_{3}}\]

C)

\[N{{H}_{2}}OH\]

D)

\[{{N}_{2}}{{H}_{4}}\]

View Solution

42)

Which of the following are peroxoacids of sulphur?

A)

\[{{H}_{2}}{{S}_{2}}{{O}_{7}}\] and \[{{H}_{2}}{{S}_{2}}{{O}_{8}}\]

B)

\[{{H}_{2}}S{{O}_{5}}\] and \[{{H}_{2}}{{S}_{2}}{{O}_{8}}\]

C)

\[{{H}_{2}}{{S}_{2}}{{O}_{6}}\] and \[{{H}_{2}}{{S}_{2}}{{O}_{8}}\]

D)

\[{{H}_{2}}{{S}_{2}}{{O}_{6}}\] and \[{{H}_{2}}{{S}_{2}}{{O}_{7}}\]

View Solution

43)

Covalency of oxygen cannot exceed 2 unlike sulphur which can show +4 or +6 because

A)

oxygen atom does not have d-orbitals

B)

oxygen atom has two unpaired electrons in its valence shell

C)

oxygen can form a double bond with another oxygen atom

D)

electrons of oxygen atom cannot be promoted to d-orbitals due to its small size.

View Solution

44)

Which of the following reactions show the reducing property of hydrochloric acid?

A)

\[ZnC{{O}_{3}}+2HCl\to ZnC{{l}_{2}}+{{H}_{2}}O+C{{O}_{2}}\]

B)

\[Mg+2HCl\to MgC{{l}_{2}}+{{H}_{2}}\]

C)

\[Mn{{O}_{2}}+4HCl\to MnC{{l}_{2}}+2{{H}_{2}}O+C{{l}_{2}}\]

D)

\[N{{H}_{4}}OH+HCl\to N{{H}_{4}}Cl+{{H}_{2}}O\]

View Solution

45)

Nitrogen can form only one chloride which is \[NC{{l}_{3}}\]whereas P can form \[PC{{l}_{3}}\] and \[PC{{l}_{5}}\]. This is

A)

due to absence of d-orbitals in nitrogen

B)

due to difference in size of N and P

C)

due to higher reactivity of P towards Cl than N

D)

due to presence of multiple bonding in nitrogen.

View Solution

46)

The oxidation states of most electronegative element in the product of reaction of \[Ba{{O}_{2}}\] with dil.\[{{H}_{2}}S{{O}_{4}}\] are

A)

1 and 2

B)

- 1 and + 2

C)

- 2 and - 2

D)

- 2 and - 1

View Solution

47)

Complete the given equations

(i) \[Mg+2HN{{O}_{3}}\to Mg{{(N{{O}_{3}})}_{2}}\]+W

(ii) \[Cu+8HN{{O}_{3}}\to 3Cu{{(N{{O}_{3}})}_{2}}+\]....X...\[4{{H}_{2}}O\]

(iii) \[8N{{H}_{3}}+3C{{l}_{2}}\to \]Y..+\[{{N}_{2}}\](excess)

(iv) \[{{I}_{2}}+10HN{{O}_{3}}\to \] Z\[10N{{O}_{2}}+4{{H}_{2}}O\]

A)

W	X	Y	Z
NO	\[2N{{O}_{2}}\]	\[6NC{{l}_{3}}\]	\[5HI{{O}_{3}}\]

B)

W	X	Y	Z
\[{{H}_{2}}\]	2NO	\[6N{{H}_{4}}Cl\]	\[2HI{{O}_{3}}\]

C)

W	X	Y	Z
\[{{N}_{2}}\]	\[{{N}_{2}}O\]	\[NC{{l}_{3}}\]	HI

D)

W	X	Y	Z
\[N{{O}_{2}}\]	\[{{N}_{2}}O\]	\[2N{{H}_{4}}Cl\]	3HI

View Solution

48)

Dry \[S{{O}_{2}}\] does not bleach dry flowers because

A)

nascent hydrogen responsible for bleaching is produced only in presence of moisture

B)

water is the actual reducing agent responsible for bleaching

C)

water is stronger acid than \[S{{O}_{2}}\]

D)

the \[O{{H}^{-}}\]ions produced by water cause bleaching.

View Solution

49)

Match the column I with column II and mark the appropriate choice.

	Column I		Column II
[a]	\[{{\left( CN \right)}_{2}}\]	(i)	Hydrogen bonding
[b]	\[I{{F}_{7}}\]	(ii)	Deacon's process
[c]	\[C{{l}_{2}}\]	(iii)	Pseudohalogen
[d]	HF	(iv)	\[s{{p}^{3}}{{d}^{3}}\]hybridisation

A)

[A]\[\to \](iv); [B] \[\to \](i); [C] \[\to \](iii); [D] \[\to \](ii)

B)

[A]\[\to \](ii); [B] \[\to \](iii); [C] \[\to \] (iv); [D]\[\to \](i)

C)

[A]\[\to \](iii); [B]\[\to \] (iv); [C]\[\to \] (ii); [D] \[\to \](i)

D)

[A]\[\to \](i); [B] \[\to \](ii); [C] \[\to \](iv); [D] \[\to \](iii)

View Solution

50)

Ammonia is used in detection of \[C{{u}^{2+}}\] ion because

A)

aqueous solution of \[N{{H}_{3}}\] reacts with \[C{{u}^{2+}}\] ion to form deep blue coloured complex

B)

\[N{{H}_{3}}\] reacts with \[C{{u}^{2+}}\] ion to give blue precipitate of CuO

C)

aqueous solution of \[N{{H}_{3}}\] reacts with \[C{{u}^{2+}}\] ion to form white coloured complex

D)

\[N{{H}_{3}}\] reacts with \[C{{u}^{2+}}\]ion to give green precipitate.

View Solution

51)

Xenon has closed shell configuration but is known to give compounds with fluorine because

A)

Xe atom has large size and lower ionization potential as compared to other noble gases

B)

Xe has unpaired electrons which can form covalent bonds

C)

Xe has highest boiling point hence it can form compounds with fluorine

D)

fluorine is the smallest element hence it can react with all noble gases.

View Solution

52)

Complete the following reactions by filling the appropriate choice.

[A] \[6Xe{{F}_{4}}\,\,+\,\,12{{H}_{2}}O\,\,\to \,\,4Xe\,\,+\,\,2Xe{{O}_{3}}\,\,+\underline{\,\,(i)}\,\,+\,\,\underline{(ii)}\]

[B] \[Xe{{F}_{6}}+3{{H}_{2}}O\to \underline{(iii)}+6HF\]

A)

(i)	(ii)	(iii)
\[{{F}_{2}}\]	\[{{H}_{2}}O\]	\[XeO{{F}_{4}}\]

B)

(i)	(ii)	(iii)
24HF	\[3{{O}_{2}}\]	\[Xe{{O}_{3}}\]

C)

(i)	(ii)	(iii)
2HF	\[2{{H}_{2}}O\]	XeO

D)

(i)	(ii)	(iii)
HF	\[{{H}_{2}}O\]	\[X{{e}_{2}}{{O}_{3}}\]

View Solution

53)

The element of group 17 whose half-life is in milliseconds only is

A)

Ts

B)

Te

C)

At

D)

Og

View Solution

54)

The oxidation state of sulphur in the anions \[SO_{3}^{2-}\], \[{{S}_{2}}O_{4}^{2-}\] and \[{{S}_{2}}O_{6}^{2-}\] follows the order

A)

\[{{S}_{2}}O_{6}^{2-}<{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}\]

B)

\[{{S}_{2}}O_{4}^{2-}<SO_{3}^{2-}<{{S}_{2}}O_{6}^{2-}\]

C)

\[SO_{3}^{2-}<{{S}_{2}}O_{4}^{2-}<{{S}_{2}}O_{6}^{2-}\]

D)

\[{{S}_{2}}O_{4}^{2-}<{{S}_{2}}O_{6}^{2-}<SO_{3}^{2-}\]

View Solution

55)

Which of the following statements is not correct?

A)

Helium has the lowest boiling point among the noble gases.

B)

Argon is used in electric bulbs.

C)

Krypton is obtained during radioactive disintegration.

D)

Xe forms\[Xe{{F}_{6}}\].

View Solution

56)

Among the following molecules

(i) \[Xe{{O}_{3}}\]

(ii) \[XeO{{F}_{4}}\]

(ii) \[Xe{{F}_{6}}\]

those having same number of lone pairs on Xe are

A)

(i) and (ii) only

B)

(i) and (iii) only

C)

(ii) and (iii) only

D)

(i), (ii) and (iii)

View Solution

57)

Helium is added to oxygen used by deep sea divers because

A)

it is less soluble in blood than nitrogen under high pressure

B)

it is lighter than nitrogen

C)

it is readily miscible with oxygen

D)

it is less noisonous than nitroeen.

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58)

\[Xe{{F}_{6}}\]on partial hydrolysis with water produces a compound 'X'. The same compound 'y is formed when \[Xe{{F}_{6}}\] reacts with silica. The compound 'X is

A)

\[Xe{{O}_{3}}\]

B)

\[Xe{{F}_{4}}\]

C)

\[Xe{{F}_{2}}\]

D)

\[XeO{{F}_{4}}\]

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59)

Colour of KI solution containing starch turns blue when chlorine water is added to it. This happens because

A)

chlorine displaces iodine from solution which gives blue colour with starch

B)

chlorine reacts with potassium iodide solution to form a blue precipitate

C)

iodine which is liberated is more soluble in KI resulting in blue colour

D)

chlorine acts as bleaching agent which decolourises KI and becomes blue

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60)

Bond angle in \[{{H}_{2}}O\,\,(104.5{}^\circ )\] is higher than the bond angle of \[{{H}_{2}}S\,\,(92.1{}^\circ )\]. The difference is due to

A)

O is diatomic and S is tetra-atomic

B)

difference in electronegativity of S and O

C)

difference in oxidation states of S and O

D)

difference in shapes of hybrid orbitals of S and O.

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12th Class Chemistry The p-Block Elements-I / p-ब्लॉक के कुछ तत्व-I Question Bank

done MCQs - The p-Block Elements Total Questions - 60

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MCQs - The p-Block Elements

MCQs - The p-Block Elements Total Questions - 60