A) \[ZnC{{O}_{3}}+2HCl\to ZnC{{l}_{2}}+{{H}_{2}}O+C{{O}_{2}}\]
B) \[Mg+2HCl\to MgC{{l}_{2}}+{{H}_{2}}\]
C) \[Mn{{O}_{2}}+4HCl\to MnC{{l}_{2}}+2{{H}_{2}}O+C{{l}_{2}}\]
D) \[N{{H}_{4}}OH+HCl\to N{{H}_{4}}Cl+{{H}_{2}}O\]
Correct Answer: C
Solution :
HCl is oxidised by strong oxidising agents like manganese dioxide, lead dioxide, potassium permanganate, potassium dichromate, etc. hence acts as a reducing agent. \[Mn{{O}_{2}}+4HCl\to MnC{{l}_{2}}+2{{H}_{2}}O+C{{l}_{2}}\]
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