| Bond angle in \[{{H}_{2}}O\,\,(104.5{}^\circ )\] is higher than the bond angle of \[{{H}_{2}}S\,\,(92.1{}^\circ )\]. The difference is due to |
  |
A) O is diatomic and S is tetra-atomic
B) difference in electronegativity of S and O
C) difference in oxidation states of S and O
D) difference in shapes of hybrid orbitals of S and O.
Correct Answer: B
Solution :
difference in electronegativity of S and O
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