Mensuration
Category : 7th Class
Mensuration
Standard Units of Area
The inter relationship among various units of measurement of area are listed below.
\[1{{m}^{2}}~~~~~~~=\text{ }\,\,\left( 100\text{ }\times \text{ }100 \right)\text{ }c{{m}^{2}}=\text{ }{{10}^{4}}c{{m}^{2}}\]
\[1\text{ }{{m}^{2}}~~~~~~~=\text{ }\left( 10\text{ }\times \text{ }10 \right)\text{ }d{{m}^{2}}=\text{ }100\text{ }d{{m}^{2}}\]
\[1\text{ }d{{m}^{2}}~~~~~~=\text{ }\left( 10\text{ }\times \text{ }10 \right)\text{ }c{{m}^{2}}=\text{ }100\text{ }c{{m}^{2}}\]
\[1\text{ }da{{m}^{2}}~~~~~=\text{ }\left( 10\text{ }\times \text{ }10 \right)\text{ }r{{n}^{2}}=\text{ }100\text{ }{{m}^{2}}\]
\[1\text{ }h{{m}^{2}}~~~~~~=\text{ }\left( 100\text{ }\times \text{ }100 \right)\text{ }{{m}^{2}}=\text{ }{{10}^{4}}{{m}^{2}}\]
\[1\text{ }k{{m}^{2}}~~~~~~=\text{ }\left( 1000\text{ }\times \text{ }1000 \right)\text{ }{{m}^{2}}=\text{ }{{10}^{6}}{{m}^{2}}\]
\[1\text{ }hectare~~=\text{ }\,10000{{m}^{2}}\]
\[1\,\,k{{m}^{2}}~~~~~~=\,\,\,100\text{ }hectare\]
Formula Related to Perimeter and Area
Find the area of a triangle whose sides are 15 cm, 9 cm and 2 cm.
(a) 48 \[c{{m}^{2}}\] (b) 80 \[c{{m}^{2}}\]
(c) 54 \[c{{m}^{2}}\] (d) 78 \[c{{m}^{2}}\]
(e) None of these
Ans. (c)
Explanation: Here \[a\text{ }=\text{ }15\text{ }cm,\text{ }b\text{ }=\text{ }9\text{ }cm\text{ }and\text{ }c\text{ }=\text{ }12\text{ }cm\]
Also, \[{{a}^{2}}=\text{ }{{b}^{2}}+\text{ }{{c}^{2}}\Rightarrow \] The given triangle is a right triangle.
\[\therefore \text{ }Area\text{ }of\text{ }the\text{ }right\text{ }triangle\text{ }=\text{ }\frac{1}{2}\text{ }\times \text{ }9\text{ }\times \text{ }12\text{ }=\text{ }54\text{ }c{{m}^{2}}\]
The dimensions of the floor of a room are 15 m and 20 m« How many square tiles each of length 20 cm are required to furnish the floor?
(a) 2,400 (b) 5,200
(c) 7,500 (d) 5,250
(e) None of these
Ans. (c)
Explanation: \[Area\text{ }of\text{ }the\text{ }room\text{ }=\text{ }15\text{ }m\text{ }\times \text{ }20\text{ }m\]
\[=\text{ }1500\text{ }cm\text{ }\times \text{ }2000\text{ }cm\text{ }=\text{ }3\text{ }\times \text{ 1}{{\text{0}}^{6}}c{{m}^{2}}\]
\[Area\text{ }of\text{ }a\text{ }tile\text{ }=\text{ }20\text{ }cm\text{ }\times \text{ }20\text{ }cm\text{ }=\text{ }400\text{ }c{{m}^{2}}\]
Total number of tiles required \[=\,\,\frac{3\times {{10}^{6}}}{400}\,\,=\,\,\frac{30000}{4}=\,\,7,500\]
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