Simplifying Arithmetic Expressions
Category : 7th Class
To simplify arithmetic expression follow BODMAS RULE
The value of \[~24-52\left\{ 5-\overline{\left( 13-8 \right)} \right\}\div \left[ 8\text{ }\{5+\left( -7 \right)\times \left( -9 \right)\} \right]\] is ......
(a) 124
(b) \[-24\]
(c) \[-529\]
(d) \[-\left( -24 \right)\]
(e) None of these
Answer: (d)
Explanation
We have: \[24-52\left\{ 5-\left( 13-8 \right) \right\}\div \left[ 8\text{ }\{5\text{ }+\left( -7 \right)\times \left( -9 \right)\} \right]\]
\[=24-52\left\{ 5-5 \right\}\div \left[ 8\{5+63\} \right]\]
\[=24-52\times 0\div \left[ 8\text{ }x\text{ }68 \right]\]
\[=24-52\times 0\div 544\]
\[=24-52\times 0\]
\[=24\]
we can write 24 as \[-\left( -24 \right)\] also.
Pamela tries to use bracket for a mathematical expression "twenty four multiplied by twelve more than the difference of twenty three and five". The correct representation is.
(a) \[24\times \left\{ \left( 23-5 \right)+12 \right\}\]
(b) \[24\times \left\{ \left( 23-5 \right) \right\}+12\]
(c) \[24\times \left( 23-5+12 \right)\]
(d) \[24\times 23-5+12\]
(e) None of these
Answer: (a)
Explanation
The correct representation is \[24\times \left\{ \left( 23-5 \right)+12 \right\}\]
The value of \[29-2\left\{ 6-\left( 7-3 \right) \right\}+\left[ 3\times \{5+\left( -3 \right)\times \left( -2 \right)\} \right]\]is____.
(a) 58
(b) -59
(c) 57
(d) 59
(e) None of these
Answer: (a)
If \[P=45-\left[ 5+\{60-\left( 39-8 \right)\} \right]\]and \[Q=-12+\left[ 25-2\{16-9\} \right]\] than then \[\left| P \right|+\left| Q \right|=?\]\[\left| P \right|+\left| Q \right|=?\]
(a) 10
(b) \[-10\]
(c) 20
(d) 12
(e) None of these
Answer: (d)
Explanation
\[p=45-[5+\{60-(39-8)\}]=45-[5+\{60-31\}]\]
\[=45-\left( 5+29 \right]=45-34=11\]and \[Q=-12+\left[ 25-\{2\left( 16-9 \right)\} \right]\]
\[=-12+\left[ 25-\{2\times 7\} \right]=-12+\left[ 25-14 \right]=-12+11=-1\]
Hence \[\left| P \right|+\left| Q \right|=\left| 11 \right|+\left| -1 \right|=11+1=12\]
There are two integers X and Y such that 5 and T are their additive inverse respectively then \[\left| X \right|+\left| Y \right|+\left| S \right|+\left| T \right|\] is equal to
(a)\[\left| X \right|\]
(b) \[\left| Y \right|+\left| S \right|\]
(c)\[2\left( \left| X \right|+|Y| \right)\]
(d) \[\left| X \right|+\left| Y \right|\]
(e) None of these
Answer: (c)
Explanation
Here, \[\left| S \right|=\left| X \right|\]and \[\left| T \right|=\left| Y \right|\]hence,
\[\left| X \right|+\left| Y \right|+\left| S \right|+\left| T \right|\]\[=\left| X \right|+\left| Y \right|+\left| X \right|+\left| Y \right|=2\left( \left| X \right|+|Y| \right)\]
If\[P=\left[ 29-\left( -2 \right)\{6-\left( 7-3 \right)\} \right]\]and \[Q=\left[ 3\times \{5+\left( -3 \right)\times \left( -2 \right)\} \right]\]then P - Q is equal to
(a) 10
(b) 1
(c) -1
(d) 2
(e) None of these
Answer: (b)
You need to login to perform this action.
You will be redirected in
3 sec