| (i) \[88\,g\,of\,C{{O}_{2}}\] | (a) \[0.25\,mol\] |
| (ii) \[6.022\times {{10}^{23}}\] Molecules of \[{{H}_{2}}O\] | (b) \[2\,mol\] |
| (iii) 5.6 litres of \[{{O}_{2}}\] at STP | (c) 1 mol |
| (iv) \[96\,g\]of \[{{O}_{2}}\] | (d) \[6.022\times {{10}^{23}}\]molecules |
| (v) \[1\,mol\]of any gas | (e) \[3\,mol\] |
Answer:
(i) ? (b) 88 g \[C{{O}_{2}}\]
contains 2 mol
(ii) ? (c) \[6.023\times
{{10}^{23}}\] molecules of \[{{H}_{2}}O\] = 1 mol
(iii) ? (a) Number of moles of
\[{{O}_{2}}\frac{5.6}{22.4}=0.25mol\]
(iv) ? (e) Number of moles in \[96\,g\,{{O}_{2}}=\frac{96}{32}=3\]
(v) ? (d) 1 mol of any gas
contains \[6.023\times {{10}^{23}}\]molecules
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