11th Class Chemistry Some Basic Concepts of Chemistry

  • question_answer 79)   The reactant which is entirely consumed in reaction is known as limiting reagent. In the reaction \[2A+4B\to 3C+4D\], when 5 moles of A react with 6 moles of B, then : (a) which is the limiting reagent? (b) calculate the amount of C formed.

    Answer:

      The given reaction is : \[\underset{2mol}{\mathop{2A}}\,+\underset{4mol}{\mathop{4B}}\,\to \underset{3mol}{\mathop{3C}}\,+\underset{4mol}{\mathop{4D}}\,\] Given moles of A and B are 5 and 6 moles respectively. Case I:   Let reactant (A) is completely consumed. 2 mol A \[\equiv \] 3 mol C \[\therefore \]  \[5molA\equiv \frac{3}{2}\times 5molC\equiv 7.5\,molC\] Case II: Let reactant (B) is completely consumed. 4 mol 5 \[\equiv \] 3 mol C \[\therefore \]  \[6\text{ }mol\text{ }B\equiv \frac{3}{4}\times 6mol\text{ }C\text{ }\equiv \text{ }4.5\text{ }mol\text{ }C\] Since (B) on complete consumption gives least amount of product (C) hence (B) will be limiting reagent and the amount of (C) formed will be 4.S mol.


You need to login to perform this action.
You will be redirected in 3 sec spinner