RAJASTHAN PMT Rajasthan - PMT Solved Paper-2006

  • question_answer
    A sphere of diameter 0.2 m and mass 2 kg is rolling on an inclined plane with velocity v = 0.5 m/s. The kinetic energy of the sphere is:

    A)  0.1 J                                     

    B)         0.3 J

    C)         0.5 J                                     

    D)         0.42 J

    Correct Answer: D

    Solution :

    The kinetic energy of sphere while rolling on an inclined plane is given by \[{{E}_{K}}=\]Translational kinetic energy-Rotational kinetic energy                 \[=\frac{1}{2}m{{v}^{2}}+\frac{1}{2}I{{\omega }^{2}}\]         \[{{E}_{K}}=\frac{1}{2}\times 2\times {{(0.5)}^{2}}+\frac{1}{2}\times \frac{2}{3}\times \]                                                                                                                                       \[{{(0.1)}^{2}}\times {{\left( \frac{0.5}{0.1} \right)}^{2}}\]


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