A) \[1.57\times {{10}^{6}}T\]
B) \[1.57\times {{10}^{-5}}T\]
C) \[1.57\times {{10}^{-4}}T\]
D) \[1.57T\]
Correct Answer: C
Solution :
\[n=10,r=2\,cm=2\times {{10}^{2}}\,m,\,i=0.5\text{A}\]Magnetic field at the centre of a circular coil \[B=\frac{{{\mu }_{0}}ni}{2r}\] \[=\frac{4\pi \times {{10}^{-7}}\times 10\times 0.5}{2\times 2\times {{10}^{-2}}}\] \[=5\pi \times {{10}^{-5}}=5\times 3.14\times {{10}^{-5}}\text{T}\] \[=157\times {{10}^{-4}}\text{T}\]
You need to login to perform this action.
You will be redirected in
3 sec
