RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    When neutrons are bombarded on \[_{5}{{B}^{10}}\]then\[_{5}{{B}^{10}}+{{1}_{{{n}_{0}}}}\xrightarrow{{}}X{{+}_{2}}H{{e}^{4}},X\] is:

    A)  \[_{3}L{{i}^{7}}\]                            

    B)         \[_{3}L{{i}^{6}}\]  

    C)  \[_{5}B{{e}^{8}}\]                          

    D)         \[_{5}B{{e}^{12}}\]

    Correct Answer: A

    Solution :

    \[_{5}{{B}^{10}}{{+}_{0{{n}^{1}}}}{{\xrightarrow{{}}}_{3}}L{{i}^{7}}{{+}_{2}}H{{e}^{4}}\] Total atomic number and mass number should be same on both sides of the equation.


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