RAJASTHAN PMT Rajasthan - PMT Solved Paper-2000

  • question_answer
    Remaining quantity (in %) of radioactive element after 5 half lives:

    A)  4.125%

    B)                                         3.125%

    C)  31.1%                  

    D)         42.125%

    Correct Answer: B

    Solution :

    Remaining quantity \[N={{N}_{0}}{{\left( \frac{1}{2} \right)}^{n}}\] \[\begin{align}   & ={{N}_{0}}{{\left( \frac{1}{2} \right)}^{5}}=\frac{{{N}_{0}}}{32} \\  & =\frac{{{N}_{0}}}{30\times {{N}_{0}}}\times 100=3.125\,% \\ \end{align}\]


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