A) \[v=-cs\]
B) \[c=-vs\]
C) \[{{v}^{2}}={{c}^{2}}s\]
D) \[{{c}^{2}}={{v}^{2}}s\]
Correct Answer: A
Solution :
Let the wave equation \[y=A\sin (\omega t-kx)\] then \[v=\frac{dy}{dt}A\omega \cos (\omega t-kx)\] and \[s=\frac{dy}{dx}Ak\cos (\omega t-kx)\] \[=\frac{-kv}{\omega }=-\frac{v}{c}\] \[v=-cs\]
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