RAJASTHAN ­ PET Rajasthan PET Solved Paper-2003

  • question_answer
    The value of resistance R will be

    A)  10\[\Omega \]

    B)  15\[\Omega \]

    C)  20\[\Omega \]

    D)  25\[\Omega \]

    Correct Answer: D

    Solution :

     Current in resistance\[R=4A\] \[\therefore \] \[R=\frac{V}{I}=\frac{100}{4}\] \[=25\,\Omega \]


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