A) H
B) \[{{H}^{+}}\]
C) \[L{{i}^{++}}\]
D) Deuteron
Correct Answer: C
Solution :
In outer orbit of\[H,H{{e}^{+}}\]and\[L{{i}^{++}}\]one electron is present and due to less attraction of nucleus of\[L{{i}^{++}}\]its ionic radius will also be minimum.
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