A) 30%
B) 50%
C) 90%
D) 10%
Correct Answer: C
Solution :
| The efficiency of transfer |
| \[\text{=}\frac{\text{Energy}\,\text{obtained}\,\text{from}\,\text{the}\,\text{secondary}\,\text{coil}}{\text{Energy}\,\text{given}\,\text{to}\,\text{the}\,\text{primary}\,\text{coil}}\] |
| or \[\eta \text{=}\frac{\text{Output}\,\text{power}}{\text{Input}\,\text{power}}\] |
| or \[\eta =\frac{{{V}_{s}}{{I}_{s}}}{{{V}_{p}}{{I}_{p}}}\] |
| Given, \[{{V}_{s}}{{I}_{s}}=100\,W,\,{{V}_{p}}=220\,\,V,\,{{I}_{p}}=0.5\,A\] |
| Hence, \[\eta =\frac{100}{220\times 0.5}=0.90=90%\] |
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