A) 90 V
B) 120 V
C) 220 V
D) 30 V
Correct Answer: B
Solution :
The magnetic flux linked with the primary coil is given by |
\[\phi ={{\phi }_{0}}+4\,t\] |
So, voltage across primary |
\[{{V}_{P}}=\frac{d\phi }{dt}=\frac{d}{dt}({{\phi }_{0}}+4t)\] |
= 4 volt (as \[{{\phi }_{0}}=\] constant) |
Also, we have |
\[{{N}_{p}}=50\] and \[{{N}_{s}}=1500\] |
From relation, |
\[\frac{{{V}_{s}}}{{{V}_{p}}}=\frac{{{N}_{s}}}{{{N}_{p}}}\] |
or \[{{V}_{s}}={{V}_{p}}\frac{{{N}_{s}}}{{{N}_{p}}}\] |
\[=4\left( \frac{1500}{50} \right)\] |
\[=120\text{ }V\] |
Note: As in case of given transformer, voltage if secondary is increased, hence it is a step-up transformer. |
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