Manipal Medical Manipal Medical Solved Paper-2013

  • question_answer
    The radius of hydrogen atom in the ground state is\[0.53\overset{o}{\mathop{\text{A}}}\,\]. The radius of\[L{{i}^{2+}}\]ion (atomic number = 3) in a similar state is

    A)  \[0.17\overset{o}{\mathop{\text{A}}}\,\]  

    B)  \[0.265\overset{o}{\mathop{\text{A}}}\,\] 

    C)  \[0.53\overset{o}{\mathop{\text{A}}}\,\] 

    D)  \[1.06\overset{o}{\mathop{\text{A}}}\,\]

    Correct Answer: A

    Solution :

     \[{{r}_{n}}=\frac{{{n}^{2}}{{a}_{0}}}{Z}\] \[{{r}_{1}}(H)=\frac{{{a}_{0}}}{Z}={{a}_{0}}=0.53\overset{o}{\mathop{\text{A}}}\,\] \[{{r}_{1}}(L{{i}^{2+}})=\frac{{{a}_{0}}}{3}=\frac{0.53}{3}=0.17\overset{o}{\mathop{\text{A}}}\,\]


You need to login to perform this action.
You will be redirected in 3 sec spinner