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Manipal Medical Manipal Medical Solved Paper-2001

  • question_answer
    At\[27{}^\circ C\]the kinetic energy of an ideal monoatomic gas is:

    A)  300K           

    B)  900K

    C)  600K           

    D)  1200K

    Correct Answer: B

    Solution :

     We know that kinetic energy\[=\frac{3}{2}RT\] \[R=2cal\] \[T=27+273=300\text{ }K\] By putting the values we have K.E. \[=\frac{3}{2}\times 2\times 300\] \[=900\text{ }K\]


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