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Manipal Medical Manipal Medical Solved Paper-2001

  • question_answer
    \[CH=CH+{{H}_{2}}O\xrightarrow[{}]{{{H}_{2}}S{{O}_{4}}+HgS{{O}_{4}}}X\] X is identified as

    A)  ketone

    B)  ethanol

    C)  acetaldehyde

    D)  propionaldehyde

    Correct Answer: C

    Solution :

     \[CH=CH+{{H}_{2}}O\xrightarrow[{}]{HgS{{O}_{4}}+{{H}_{2}}S{{O}_{4}}}\] \[\underset{CHOH}{\overset{C{{H}_{2}}}{\mathop{||}}}\,\xrightarrow[{}]{900\,K}\underset{X}{\mathop{C{{H}_{3}}CHO}}\,\] Thus X is identified as acetaldehyde


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