A) (2, 2)
B) (3, 1)
C) (4, 0)
D) (5, 2)
Correct Answer: D
Solution :
We have, \[\underset{h\to 0}{\mathop{\lim }}\,f(1-h)=\underset{h\to 0}{\mathop{\lim }}\,{{(1-h)}^{2}}+b=a+b\] \[\Rightarrow \]\[\underset{h\to 0}{\mathop{\lim }}\,f(1+h)=\underset{h\to 0}{\mathop{\lim }}\,(1+h)+3=4\] and\[f(1)=4\] \[\therefore \]\[f(x)\]will not be continuous at\[x=1\], if\[a+b\ne 4\]You need to login to perform this action.
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