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Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    A body of mass\[x\]kg is moving with a velocity of\[100\,\,m{{s}^{-1}}\].   Its de-Broglie wavelength is\[6.62\times {{10}^{-35}}m\]. Hence,\[x\]is\[(h=6.62\times {{10}^{-34}}Js)\]

    A)  0.1 kg   

    B)                                         0.25 kg

    C)  0.15kg                 

    D)         0.2kg   

    Correct Answer: A

    Solution :

    \[\lambda =\frac{h}{mv}\] \[=\frac{6.62\times {{10}^{-34}}}{6.62\times {{10}^{-35}}\times 100}\]


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