Manipal Engineering Manipal Engineering Solved Paper-2009

  • question_answer
    The correct set of four quantum numbers for outermost electron of potassium\[(Z=19)\]is

    A) \[4,\,\,1,\,\,0,\,\,\frac{1}{2}\]    

    B)        \[3,\,\,1,\,\,0,\,\,\frac{1}{2}\]

    C) \[4,\,\,0,\,\,0,\,\,\frac{1}{2}\]    

    D)        \[3,\,\,0,\,\,0,\,\,\frac{1}{2}\]

    Correct Answer: C

    Solution :

    \[K(19):\,\,1{{s}^{2}},\,\,2{{s}^{2}}2{{p}^{6}},\,\,3{{s}^{2}}3{{p}^{6}},\,\,4{{s}^{1}}\] \[4{{s}^{1}}\]is the valence electron in potassium, hence the correct set of four quantum numbers for outermost electron is\[4,\,\,0,\,\,0,\,\,\frac{1}{2}\].


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