JEE Main & Advanced JEE Main Online Paper (Held on 9 April 2013)

  • question_answer                 Anether (A) \[{{\operatorname{C}}_{5}}{{\operatorname{H}}_{12}}\operatorname{O},\]when heated with excess of hot concentrated HI produced two alky halides which when treated with NaOH yielded compounds (B) and (C) Oxidation of (B) and (C) gave a propanone and an ethanoic acid respectively. The IUPAC name of the ether (A) is:           JEE Main Online Paper (Held On 09 April 2013)        

    A)                 2-ethoxypropane                

    B)                 ethoxypropane                

    C)                 methoxybutane                

    D)                        2-methoxybutane                

    Correct Answer: A

    Solution :

                     Ether (A) is 2-ethoxypropane \[{{C}_{3}}{{H}_{7}}-O-{{C}_{2}}{{H}_{5}}\]                                  

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