Solved papers for JEE Main & Advanced AIEEE Solved Paper-2009

done AIEEE Solved Paper-2009

  • question_answer1)
    Direction: Q. No. 1 The question contains Statement-I and Statement-II of the four Choices given after the statements, choose the one that best describe the two statements. STATEMENT-1 For a charged particle moving from point P to point Q, the net work done by an electrostatic field on the particle is independent of the path connected point P to point Q. STATEMENT-2 The net work done by a conservative force on an object moving along a closed loop is zero.     AIEEE  Solved  Paper-2009  

    A)
    Statement - 1 is True, Statement - 2 is False.

    B)
    Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.

    C)
    Statement-1 is True, Statement-2 is True; Statement-2 is not the correct explanation for Statement-1.

    D)
    Statement - 1 is False, Statement - 2 is true.

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  • question_answer2)
    Let\[p(r)=\frac{Q}{\pi {{R}^{4}}}r\]be the charge density distribution for a solid sphere of radius R and total charge Q. For a point 'p' inside the sphere at distance\[{{r}_{1}}\]from the centre of sphere, the magnitude of electric field is     AIEEE  Solved  Paper-2009

    A)
    0                                             

    B)
    \[\frac{Q}{4\pi {{\varepsilon }_{0}}r_{1}^{2}}\]  

    C)
           \[\frac{Qr_{1}^{2}}{4\pi {{\varepsilon }_{0}}{{R}^{4}}}\]

    D)
           \[\frac{Qr_{1}^{2}}{3\pi {{\varepsilon }_{0}}{{R}^{4}}}\]

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  • question_answer3)
    Two points P and Q are maintained at the potentials of 10V and -4V, respectively. The work done in moving 100 electrons from P to Q is     AIEEE  Solved  Paper-2009

    A)
    \[9.60\times {{10}^{17}}J\]         

    B)
    \[9.60\times {{10}^{17}}J\]

    C)
           \[2.24\times {{10}^{16}}J\]

    D)
           \[2.24\times {{10}^{16}}J.\]

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  • question_answer4)
    A charge Q is placed at each of the opposite corners of a square. A charge q is placed at each of the other tow corners. If the net electrical force on Q is zero, then Q/q equals:     AIEEE  Solved  Paper-2009

    A)
    \[-2\sqrt{2}\]

    B)
           -1                           

    C)
           1                             

    D)
           \[-\frac{1}{\sqrt{2}}\]

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AIEEE Solved Paper-2009
 

   


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