JEE Main & Advanced AIEEE Solved Paper-2009

  • question_answer
    A charge Q is placed at each of the opposite corners of a square. A charge q is placed at each of the other tow corners. If the net electrical force on Q is zero, then Q/q equals:     AIEEE  Solved  Paper-2009

    A) \[-2\sqrt{2}\]

    B)        -1                           

    C)        1                             

    D)        \[-\frac{1}{\sqrt{2}}\]

    Correct Answer: A

    Solution :

    \[\frac{KQ}{2{{a}^{2}}}=\sqrt{2}\frac{Kq}{{{a}^{2}}}\] \[\Rightarrow \]\[\left| \frac{Q}{q} \right|=2\sqrt{2}\] So, \[\frac{Q}{q}=-2\sqrt{2}\]


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