2. Solved Papers
  3. JCECE Engineering

JCECE Engineering JCECE Engineering Solved Paper-2013

  • question_answer
    A body is projected with velocity \[{{v}_{1}}\] from the point\[A\], another body at the same time is projected vertically upwards from \[B\] with velocity \[{{v}_{2}}\] as shown in adjoining figure. If the point \[B\] lies vertically below the highest point \[C\], then for both bodies to collide the ratio\[\frac{{{v}_{2}}}{{{v}_{1}}}\]should be

    A) \[0.5\]                                  

    B) \[1\]

    C) \[\frac{\sqrt{3}}{2}\]                                     

    D) \[\frac{2}{\sqrt{3}}\]

    Correct Answer: A

    Solution :

    The two bodies will collide at the highest point if both cover the same vertical height in the same time. So,          \[\frac{v_{1}^{2}{{\sin }^{2}}{{30}^{o}}}{2g}=\frac{v_{2}^{2}}{2g}\] or            \[\frac{v_{2}^{2}}{v_{1}^{2}}={{\sin }^{2}}{{30}^{o}}\] \[\Rightarrow \]               \[\frac{{{v}_{2}}}{{{v}_{1}}}=\sin {{30}^{o}}=\frac{1}{2}=0.5\]


You need to login to perform this action.
You will be redirected in 3 sec spinner