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JCECE Engineering JCECE Engineering Solved Paper-2013

  • question_answer
    If a force of \[4\,\,N\] is applied on a body of mass \[20\,\,kg\], then the work done in 3rd second will be

    A) \[1.2\,\,J\]                         

    B) \[2\,\,J\]

    C)  \[4\,\,J\]                                            

    D)  \[16\,\,J\]

    Correct Answer: B

    Solution :

    Here,\[a=\frac{f}{m}=\frac{4}{20}=\frac{1}{5}m/{{s}^{2}}\] Distance travelled by body in 3rd second                 \[{{S}_{3rd}}=0+\frac{1}{5\times 2}(2\times 3-1)=0.5\,\,m\] Hence, work done, \[W=f\times {{S}_{3rd}}=4\times 0.5=25\,\,J\]


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