2. Solved Papers
  3. Haryana PMT

Haryana PMT Haryana PMT Solved Paper-2011

  • question_answer
    The masses of neutron and proton are 1.0087    and 1.0073 amu respectively. If the neutrons      and protons combine to form helium nucleus of            mass 4.0015 amu the binding energy of the         helium nucleus will be

    A)                  28.4 MeV                           

    B)  20.8 MeV

    C)                  27.3 MeV                           

    D)  14.2 MeV

    Correct Answer: A

    Solution :

                    Mass defect. \[\Delta m=2(1.0087+1.0073)-4.0015\]                 \[=4.032-4.0015\]                 \[=0.0305\]                 Binding energy, \[{{E}_{B}}=\Delta m\times 931Mev\]                 \[=0.0305\times 931\]                 \[=28.4MeV\]


You need to login to perform this action.
You will be redirected in 3 sec spinner