Haryana PMT Haryana PMT Solved Paper-2011

  • question_answer
    What is the % error in measurement of T of a     pendulum,   if   maximum   errors   in       measurements of (and g are 2% and 4%          respectively?

    A)                  6%                                        

    B)  3%

    C)                  4%                                        

    D)  5%

    Correct Answer: B

    Solution :

                    \[T=2\pi \sqrt{\frac{l}{g}}\]                 \[\therefore \]\[\frac{\Delta T}{T}\times 100=\frac{1}{2}\left( \frac{\Delta l}{l}+\frac{\Delta g}{g} \right)\times 100\]                 \[=\frac{1}{2}(2%+4%)=3%\]


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