A) \[\frac{3}{6}\times {{10}^{5}}\]
B) \[\frac{16}{3}\times {{10}^{15}}\]
C) \[\frac{9}{16}\times {{10}^{15}}\]
D) \[\frac{3}{4}\times {{10}^{15}}\]
Correct Answer: C
Solution :
From Bohrs theory, frequency of incident radiation \[v=RC\left( \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right)\] \[={{10}^{5}}\times {{10}^{2}}\times 3\times {{10}^{8}}\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{4}^{2}}} \right)\] \[=3\times {{10}^{15}}\left( \frac{1}{14}-\frac{1}{16} \right)\] \[=3\times {{10}^{15}}\left( \frac{3}{16} \right)\] \[=9/16\times {{10}^{15}}Hz\]
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