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CMC Medical CMC-Medical VELLORE Solved Paper-2013

  • question_answer
    A coil of area 5\[c{{m}^{2}}\] and of 20 turns is placed in uniform magnetic field of \[{{10}^{3}}\]T. The normal to the plane of the coil makes an angle of \[60{}^\circ \] with the magnetic field. The flux in Maxwell through the coil is

    A)  \[5\times {{10}^{5}}\]                  

    B)  \[5\times {{10}^{4}}\]

    C)  \[2\times {{10}^{4}}\]                  

    D)  \[5\times {{10}^{3}}\]

    Correct Answer: B

    Solution :

                    \[{{\phi }_{B}}=NAB\,\cos \theta \] \[=20\times {{10}^{3}}\times 5\times \cos 60{}^\circ \] \[=20\times {{10}^{3}}\times 5\times \frac{1}{2}\] \[=50\times {{10}^{3}}\] \[=5\times {{10}^{4}}\]


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