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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    The minimum magnifying power of a telescope is m. If the focal length of its eye lens is halved, the magnifying power will become

    A)  m/2                                      

    B)  2m

    C)  3m                                        

    D)  4m

    Correct Answer: B

    Solution :

    Minimum magnifying power of a telescope is \[m=-\frac{{{f}_{o}}}{{{f}_{e}}}\] when focal length of eye piece in halved, then                 \[m'=-\frac{{{f}_{o}}}{({{f}_{e}}/2)}=-2\frac{{{f}_{o}}}{{{f}_{e}}}\]                 \[m'=2m\]


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