A) \[\frac{3}{4}\]
B) \[\frac{3}{5}\]
C) \[\frac{\sqrt{41}}{4}\]
D) \[\frac{\sqrt{41}}{5}\]
Correct Answer: D
Solution :
Given equation is \[\frac{{{x}^{2}}}{10}-\frac{{{y}^{2}}}{25}=1\] Here, \[{{a}^{2}}=16,\,{{b}^{3}}=25\] \[(b>a)\] \[\therefore \] \[e=\sqrt{1+\frac{{{a}^{2}}}{{{b}^{2}}}}\] \[=\sqrt{1+\frac{16}{25}}=\sqrt{\frac{14}{25}}=\sqrt{\frac{41}{5}}\]
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