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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    The sum of the focal distances of any point on the conic \[\frac{{{x}^{2}}}{25}+\frac{{{y}^{2}}}{16}=1\] is :

    A)  10                                         

    B)  9

    C)  41                                         

    D)  18

    Correct Answer: A

    Solution :

    We know, if P is any point on the curve, then Sum of focal distances = length of major  cixis i.e. \[SP+SP=2a\]                                 \[=2\,(5)\]                           \[[\because \,\,{{a}^{2}}={{5}^{2}}]\]                                 \[=10\]


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