A) \[3.125\,\times {{10}^{13}}\]
B) \[6.250\,\times {{10}^{13}}\]
C) \[1.525\,\times {{10}^{13}}\]
D) None of these
Correct Answer: A
Solution :
We know that \[1\,kW=1\times {{10}^{3}}\,J/s\] Also \[1.6\times {{10}^{-19}}J=1\,eV\] \[\therefore \] \[200\,MeV=200\times 1.6\times {{10}^{-19}}\times {{10}^{6}}\,J\] Number of fissions \[=\frac{\text{Power}}{\text{Energy}\,\text{released}}\] \[=\frac{{{10}^{3}}}{200\times 1.6\times {{10}^{-13}}}\] \[=3.125\times {{10}^{13}}\]
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