JEE Main & Advanced Physics Ray Optics Sample Paper Topic Test - Refraction of Light Through Curved Surfaces

  • question_answer
    Direction: A point object O is placed at the origin of coordinate system. An equi-convex thin lens\[({{\mu }_{g}}=1.5)\] of focal length \[f=20\,cm\]in air is placed so that its principal axis is along x-axis. Now the lens is cut at the middle (along the principal axis) and upper half is shifted along x-axis and y-axis by 20 cm and 2 mm respectively and right side of lower half is filled with water \[({{\mu }_{\omega }}=4/3)\]
    Coordinates of the image produced by the lens \[{{L}_{2}}\] will be

    A) 140 cm, 0

    B) 140 cm, 20          

    C) 70 cm, 0

    D) 140 cm, 30

    Correct Answer: A

    Solution :

    By refraction formula,
    \[\frac{Mg}{{{v}_{1}}}-\frac{1}{(-60)}=\frac{Mg-1}{+20}\]            ...(i)
    \[\frac{{{\mu }_{w}}}{v}-\frac{Mg}{{{v}_{1}}}=\frac{{{\mu }_{w}}-{{\mu }_{g}}}{-20}\]    ...(ii)
    \[\therefore \]      \[v=+\,80\text{ }cm\]
    So,       \[x=v+60=+\,80+60=140\text{ }cm\]

You need to login to perform this action.
You will be redirected in 3 sec spinner