A) 6
B) 7
C) 8
D) 14
Correct Answer: A
Solution :
[a] \[\frac{a+2}{6}=\frac{b+c}{7}=\frac{c+a}{8}\] \[=\frac{a+b+b+c+c+a}{6+7+8}=\frac{2(a+b+c)}{21}=\frac{2}{21}\] \[\times 14=\frac{4}{3}\] \[\therefore \,\,\frac{a+b}{6}=\frac{4}{3}\,\,or\,=\frac{14-c}{6}=\frac{4}{3}\] \[\therefore \,\,14-c=8\,or\,\,c=6\].
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