A) \[\frac{3}{4}c{{m}^{2}}\]
B) \[\frac{3}{2}c{{m}^{2}}\]
C) \[3\,c{{m}^{2}}\]
D) \[6\,c{{m}^{2}}\]
Correct Answer: B
Solution :
[b] Clearly the triangle is a right angled as 52 =32+42. \[\therefore \] Area \[=\frac{1}{2}\times \text{ }3\text{ }\times 4\text{ }c{{m}^{2}}=6\text{ }c{{m}^{2}}.\] We know area of the triangle joining the mid-point of the given triangle \[=\frac{1}{4}\]of the area of the given triangle \[=\frac{1}{4}\times 6\,\,c{{m}^{2}}=\frac{3}{2}\,\,c{{m}^{2}}.\]
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