A) 2 L
B) L
C) 4 L
D) L/2
Correct Answer: A
Solution :
\[\because \,\,\,\,\,L\propto {{N}^{2}}{{r}^{.}},\,\,\frac{{{L}_{1}}}{{{L}_{2}}}\,\,=\,\,{{\left( \frac{{{N}_{1}}}{{{N}_{2}}} \right)}^{2}}\,\,\,\times \,\,\frac{{{r}_{1}}}{{{r}_{2}}}\] \[\Rightarrow \,\,\,\,\frac{L}{{{L}_{2}}}\,=\,\,{{\left( \frac{1}{2} \right)}^{2}}\,\times \,\,\left( \frac{r}{r/2} \right)\,\,=\,\,\frac{1}{2}\,;\,\,\,{{L}_{2}}\,\,\,=\,\,2L\]You need to login to perform this action.
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