A) \[2\times {{10}^{-5}}\,T\]
B) \[4\times {{10}^{-6}}\,T\]
C) \[8\times {{10}^{-7}}\,T\]
D) zero
Correct Answer: C
Solution :
Net magnetic field at midpoint \[P,\,\,B={{B}_{N}}\,+\,{{B}_{S}}\] \[where\,\,{{B}_{N}}=magnetic\,\,field\,\,due\,\,to\,\,N-pole\] \[{{B}_{S}}=magnetic\text{ }field\text{ }due\text{ }to\text{ }S-pole\] \[=\,\,{{10}^{-7}}\,\times \,\,\frac{0.01}{{{\left( \frac{0.1}{2} \right)}^{2}}}\] \[=\,\,4\times {{10}^{-7}}\,T\] \[\therefore \,\,\,\,{{B}_{net}}\,=\,8\times {{10}^{-7}}\,T\]You need to login to perform this action.
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